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Question about Memory Storages?

Donks said:
Yes, you can dope semiconductors with other elements.

Thanks. Btw, whether elements in crystal lattice/semiconduting form is absolutely differant in properties than its elemental atomic form? I mean; whether silicon atoms in its semiconductor form are completely differant from its silicon atom in its free/non semiconductor form in view of below quote?

In a crystal each electron "sees" the entire lattice. Therefore the available electrons will fill the available energy bands of the crystal filling the lower energy band before the higher ones.

All the available electrons fill each energy band progressively until all the electrons are occupying energy states. Once an energy band is full, the net velocity of electrons is zero. As one electron moves in one direction, another must be moving in the opposite direction. If the number of available electrons completely fills all available energy bands with few left over, the material is an insulator. The distinction of a semi-conductor comes about if the energy required to go to the next available band is small.(same previous link)
 
Kumar said:
Thanks. Btw, whether elements in crystal lattice/semiconduting form is absolutely differant in properties than its elemental atomic form? I mean; whether silicon atoms in its semiconductor form are completely differant from its silicon atom in its free/non semiconductor form in view of below quote?
You can make amorphous semiconductors, but they will be less efficient than crystalline ones.
In any case, it still does not matter. You need more than the presence of some form of Si in order to store information. You need to create memory circuits. You need to provide a voltage supply. You need lots of things that will not come from shaking water.
And another thing. When you dilute a little bit of SI in a crapload of water/alcohol/lactose, you are not doping a semiconductor. You are adding some Si impurities to the carrier. Which you then promptly remove by adding more and more water.
 
Donks said:
You can make amorphous semiconductors, but they will be less efficient than crystalline ones.
In any case, it still does not matter. You need more than the presence of some form of Si in order to store information. You need to create memory circuits. You need to provide a voltage supply. You need lots of things that will not come from shaking water.
And another thing. When you dilute a little bit of SI in a crapload of water/alcohol/lactose, you are not doping a semiconductor. You are adding some Si impurities to the carrier. Which you then promptly remove by adding more and more water.

I can't say about whole circuit, but few things are there. Hydrogen(doubtful semiconductor) in water, carbon in alcohol/lactose, silicon in contaminations, energy applied during potentization process, body heat on application of remedies, incident lights from surroundings, & active substances as doping materials are there. I can't say, whether these aspects can create some memory storage?
 
Kumar said:
I can't say about whole circuit, but few things are there. Hydrogen(doubtful semiconductor) in water, carbon in alcohol/lactose, silicon in contaminations, energy applied during potentization process, body heat on application of remedies, incident lights from surroundings, & active substances as doping materials are there. I can't say, whether these aspects can create some memory storage?
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Brian the Snail said:
I don't know. All of these people giving links to webpages on semiconductors, and nobody has linked to the best page on semiconductor physics ever. Shocking.

Plus, Kumar might at least understand the pictures.
I hadn't seen it before this thread, found it while doing research and I was about to link it but decided against it. I'm a dope sometimes :)
 
Donks said:
No.No.No.No.No.No.No......

If this No..,what other can be thought in consideration of all those aspects I mentioned in this thread.
 
If there are no electrons in the conduction band of a semi-conductor it won't conduct. To move electrons out of the valence band and into the conduction band, one needs to give them energy. This may be though heat, incident light or high electric field. As most semiconductors operate at non-zero temperature, there are generally some electrons in the conduction band. This also means that if the semi-conductor get too hot(125 degrees C) for silicon, excess electrons will exist in the conduction band, hence the semi-conductor will act more like a conductor.

The total energy of an electron is given by its momentum and its potential energy. To move an electron from the conduction band to the valence band, it may need to undergo a change in potential energy and a change in momentum. There are two basic material types, in-direct and direct band gap materials. In an indirect bang gap material, such as silicon, shown in figure 3. To move into the valence band, the electron must undergo a change in momentum and energy [1]. The chance of this event is small. Typically this process is achieved in several steps. The electron will first move to a trap site in the forbidden band before moving into the valence band. A change in potential energy will result in the release of a photon, while a change in momentum will produce a phonon. A phonon being a mechanical vibration which heats the crystal lattice.(same previous link)

Can you tell something aout bolded sentences?
 
Oh, we can tell you all sorts of things but as you lack the ability to judge what we tell you objectively or the capacity to deviate from your currently mass existing accepted from have long time beliefs, what is the point?
 
Kumar said:
If this No..,what other can be thought in consideration of all those aspects I mentioned in this thread.
Kumar, try to understand this:
The fact that semiconductors are used is irrelevant. A semiconductor does not have memory. Memory is a product of the logic circuit. To make a logic circuit you need to make logic gates. To make logic gates (in semiconductors) you use transistors. Transistors do not just appear when you shake some sand in water. Logic gates do not just appear when you shake some sand in water. Logic circuits do not just appear when you shake some sand in water.
Memory in logic circuits is used to store binary numbers. That's ones and zeros. That's it.
To record memory you need to encode your information into binary information. This will not happen by shaking some sand in water.
To read memory you need to decode your information. This will not happen by digesting a pill.
There is zero chance that homeopathy works by storing information in semiconductors in a process analogous to computer memory. Give it a freaking rest already.

Go back to square one, show that homeopathy works, then work out how. You can't currently show that it works.
 
Donks said:
Kumar, try to understand this:
The fact that semiconductors are used is irrelevant. A semiconductor does not have memory. Memory is a product of the logic circuit. To make a logic circuit you need to make logic gates. To make logic gates (in semiconductors) you use transistors. Transistors do not just appear when you shake some sand in water. Logic gates do not just appear when you shake some sand in water. Logic circuits do not just appear when you shake some sand in water.
Memory in logic circuits is used to store binary numbers. That's ones and zeros. That's it.
To record memory you need to encode your information into binary information. This will not happen by shaking some sand in water.
To read memory you need to decode your information. This will not happen by digesting a pill.
There is zero chance that homeopathy works by storing information in semiconductors in a process analogous to computer memory. Give it a freaking rest already.

Go back to square one, show that homeopathy works, then work out how. You can't currently show that it works.

Whether doped semiconductors can give specific switching effects as per the material used for doping? You may have to include human body's circuit for encoding etc.
 
Kumar said:
Whether doped semiconductors can give specific switching effects as per the material used for doping?
No. This is what's required for switching.
You may have to include human body's circuit for encoding etc.
You may have to GET YOUR HEAD OUT OF YOUR ASS to understand what people reply to you.
 
Wow. I am always amazed that people can be this stupid and still be able to use a computer. The wonders of modern technology have no limits!

Idiot, sorry, I mean, Kumar...

What switching effects are you searching for?
No, we don't have to include the body's circuit into discussion.
Encoding what?
Razzlefrantarkentontazzle is the expliztic natural frequency modulatron, were you aware?
 
Kumar said:
Whether doped semiconductors can give specific switching effects as per the material used for doping? You may have to include human body's circuit for encoding etc.

What are "specific switching effects"? "Switching" means it has two states, "on" or "off". What other effects do you imagine we're talking about?

As for the human body: Do you have light switches in your cave? Do they require some property of the human body in order to control the light? Or do they just, you know, turn it on. Or off.

And before anybody says that a human is required to turn them on or off, I'll point out that we have automated timers.
 
rppa said:
What are "specific switching effects"? "Switching" means it has two states, "on" or "off". What other effects do you imagine we're talking about?

As for the human body: Do you have light switches in your cave? Do they require some property of the human body in order to control the light? Or do they just, you know, turn it on. Or off.

And before anybody says that a human is required to turn them on or off, I'll point out that we have automated timers.

I meant, if doped semiconductors are able to connvert & conduct applied body heat in some specific pattern(as doped semiconductors do in any electronic circuit) which body/nervous system encode accordingly & show specific effects relating to doped semiconductor.

Anyway, pls tell, what happens when we apply heat to doped semiconductors? Pls tell according to input & output.
 
Kumar, you can disregard this post, as your eyes will glaze over and you'll fall asleep. This is for anyone else who's curious as to how computer memory works. It's just the basics, this is not the only way to make any of the components.

Let's start with a transistor. There are several transistor types, but that basic one will do for now. To make a transistor, you need 2 n-p junctions. That is, 2 boundaries between a n-doped region and a p-doped region.
An n-doped region is a region that has been doped with an electron donor element. That is, it has more electrons that the substrate. Typically, if Silicon is the substrate, the n-doped region will have an element with 5 electrons on its shell as a dopant.
A p-doped region is a region that has been doped with an element that will donate holes. That is, it has less electrons than the substrate. Typically, if Silicon is the substrate, the p-doped region wil have an element with 3 electrons on its shell as a dopant.
A transistor looks something like this.

Logic circuits are made of logic gates. Each gate implements a logic operation, such as AND, OR, NOT, etc. The easiest way to describe them is through their truth tables. For instance, for an AND gate (symbol)
:
Code:
v1 v2 | Output
0  0  | 0
0  1  | 0
1  0  | 0
1  1  | 1
v1 and v2 are the inputs. The gate only has an output of '1' when both inputs are '1'. The gate that I'll use to describe memory is a NAND gate (symbol)
It is a negated AND. You'll notice from the symbol that the negation is signified by the circle. The truth table is:
Code:
v1 v2 | Output
0  0  | 1
0  1  | 1
1  0  | 1
1  1  | 0
One way to construct this gate is this. It has 2 transistors, 3 resistors, a voltage source terminal (Vcc, at 6Volts), a Ground terminal (at the bottom of the image, the three horizontal lines), two input terminals (VA and VB), and one output terminal (Vout).
The way it works is this: Vout will be at 6V (approx) which signifies a '1', unless the connection with the ground terminal is established. If the connection with ground is established, Vout will be close to 0V, signifying a '0'.
The only way to establish a connection to the ground terminal is to activate both transistors, and that only happens when both inputs are '1'. So there we have a NAND gate.

Now onto the memory circuit. I'll describe one of the simplest ways to do this, an SR latch. There are other ways, but one is enough for out purposes.
The diagram for a SR latch is this. Both inputs (S and R) are negated (they have a bar on top). That means that they are active when the input is '0'. S stands for Set, R for Reset. Q is the output.
This is a sequential circuit, which means it's a bit more complicated to explain, but I'll give it a shot.

The normal input for the circuit is S=1 and R=1, that means both off. Q and Q' (Q negated) are fed back, so we need to give them startup values too. Let's start with Q=0 and Q'=1.
If S is changed to '0' (it is activated), the NAND on top has '0' and '0' as its inputs, so It turns to '1'. The NAND on the botton now has '1' and '1', so it changes to '0'. The NAND on top now has '0' and '0', so it stays at '1'. The S can now be changed back to '1', and it won't matter. The circuit has "memorized" the '1'.
To turn it back to '0', we need to use the RESET. So we leave S to '1', and we change R to '0'. The NAND on bottom has '0' and '1', so it changes to '1'. The NAND on top now has '1' and '1', so it changes to '0'. The NAND on bottom now has '0' and '0' so it stays at '1'. The R can now be set back to '1' and it won't matter. The circuit has "memorized the '0'.

And that is one way to memorize a bit using semiconductors. Now looking at Kumar's theories, what problems are there?
1) Shaking some sand in water will not create transistors. There will be no substrate, no n-p junctions, no terminals, no transistors.
2) Shaking some sand in water will not create 4 transistors in the proper configurations. There will not be 2
NAND gates properly connected.
3) Shaking some sand in water will not supply enough voltage to feed the circuit. Opening a p-n junction takes a certain ammount of voltage. That will not come from shaking water.
4) The circuit requires a continual source of voltage, otherwise the circuit forgets the information stored.
5) Storing information in binary requires encoding. To encode only lower case letters, you need at least 5 bits, giving you 32 options.That means 10 NAND gates. Typically, computers use 8 bits to store each text element. Whatever information Kumar wants to encode will not magically be transformed into the proper code, and passed to the proper input terminals.
6) Reading the information will require decoding. Cells do not decode binary information from semiconductors.
7) There are other problems, but that's enough for right now.


Kumar, in case you read all this, did you understand why your current idea is wrong? No? Too bad.
Hmm, looking at the preview I can tell that was a long and boring post. I wouldn't read it, I recomend you don't either. Maybe I should put that recomendation on top.
 

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