MarkCorrigan
Героям слава!
You may have misidentified the element of this thread that some see as a joke.
This is the person who accused several others of making callous jokes about the dead when no such thing happened though.
You may have misidentified the element of this thread that some see as a joke.
Generally, any deck angle greater than 20° defeats ordinary locomotion. You shift into a different kind of movement that's slower and more awkward.
But what about the conspiracies? sabotage? murders? nukes? disappeared crew? Surely they must all be mentioned prominently?
How many Volvos did she see?
And Volvos. Volvo is Latin for I roll. Suspicious.
Finally made it to the end of the threads!
And Volvos. Volvo is Latin for I roll. Suspicious.
Finally made it to the end of the threads!
Welcome to the end of the threads!
The thread never ends. Unless Vixen actually sticks to "I am out".
Until tomorrow, then, at least.
Are you sure about that?
To determine the force exerted when a ship hits the seabed, we need to consider the concept of pressure. Pressure is defined as force per unit area. We can calculate the force exerted by the ship using the formula:
Force = Pressure × Area
Given that the ship hits the seabed at a depth of 80 meters, we need to calculate the pressure at that depth. The pressure in a fluid increases with depth due to the weight of the fluid above. The pressure at a specific depth can be calculated using the formula:
Pressure = Density × Gravitational acceleration × Depth
The density of seawater is typically around 1,025 kilograms per cubic meter, and the gravitational acceleration is approximately 9.8 meters per second squared.
Let's calculate the force exerted by the ship:
Pressure = Density × Gravitational acceleration × Depth
= 1,025 kg/m³ × 9.8 m/s² × 80 m
≈ 803,600 Pa (Pascals)
Next, we need to determine the area over which the force is distributed. Without additional information about the shape or size of the ship's contact area, it is difficult to provide an exact value. However, we can assume a simple approximation that the area of contact is the same as the ship's bottom surface area.
Let's say the ship has a bottom surface area of 1000 square meters (just for illustration purposes).
Force = Pressure × Area
= 803,600 Pa × 1000 m²
= 803,600,000 N (Newtons)
Therefore, if the ship weighs 15,000 tonnes and hits the seabed at a depth of 80 meters, it exerts an approximate force of 803,600,000 Newtons (or 803.6 meganewtons) on the seabed. Please note that these calculations are based on estimations and assumptions, and the actual force may vary depending on the ship's design and the specific circumstances of the impact.
I go away for nearly a year and the thread is going over and over the same ground that has already been gone over in excruciating detail.
Amazing
Happy to see you back, captain. Sorry you missed last month's futile fringe reset.
Maybe when the wreck's ramp is recovered and examined Vixen will return from self-imposed exile to tell us what the report on it means.
I go away for nearly a year and the thread is going over and over the same ground that has already been gone over in excruciating detail.
Amazing