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Cont: The Sinking of MS Estonia: Case Reopened Part V

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Generally, any deck angle greater than 20° defeats ordinary locomotion. You shift into a different kind of movement that's slower and more awkward.

As a kid, my favorite attraction at an amusement park was the tunnel that was a spinning tube. Hours of fun though I had many bruises afterword. I can't imagine what the passengers went through in those final minutes, but the idea that the command crew not making it out is a mystery, is laughable. If anything, it means they were trying to do their jobs.
 
The following post was created using a generative AI system but was not labelled as such as per Rule 4. Unfortunately we do not know which one nor the prompt used, when we do I'll update this post.
Replying to this modbox in thread will be off topic  Posted By: Darat
Are you sure about that?


To determine the force exerted when a ship hits the seabed, we need to consider the concept of pressure. Pressure is defined as force per unit area. We can calculate the force exerted by the ship using the formula:

Force = Pressure × Area

Given that the ship hits the seabed at a depth of 80 meters, we need to calculate the pressure at that depth. The pressure in a fluid increases with depth due to the weight of the fluid above. The pressure at a specific depth can be calculated using the formula:

Pressure = Density × Gravitational acceleration × Depth

The density of seawater is typically around 1,025 kilograms per cubic meter, and the gravitational acceleration is approximately 9.8 meters per second squared.

Let's calculate the force exerted by the ship:

Pressure = Density × Gravitational acceleration × Depth
= 1,025 kg/m³ × 9.8 m/s² × 80 m
≈ 803,600 Pa (Pascals)

Next, we need to determine the area over which the force is distributed. Without additional information about the shape or size of the ship's contact area, it is difficult to provide an exact value. However, we can assume a simple approximation that the area of contact is the same as the ship's bottom surface area.

Let's say the ship has a bottom surface area of 1000 square meters (just for illustration purposes).

Force = Pressure × Area
= 803,600 Pa × 1000 m²
= 803,600,000 N (Newtons)

Therefore, if the ship weighs 15,000 tonnes and hits the seabed at a depth of 80 meters, it exerts an approximate force of 803,600,000 Newtons (or 803.6 meganewtons) on the seabed. Please note that these calculations are based on estimations and assumptions, and the actual force may vary depending on the ship's design and the specific circumstances of the impact.
 
I go away for nearly a year and the thread is going over and over the same ground that has already been gone over in excruciating detail.

Amazing
 
I go away for nearly a year and the thread is going over and over the same ground that has already been gone over in excruciating detail.

Amazing

Happy to see you back, captain. Sorry you missed last month's futile fringe reset.

Maybe when the wreck's ramp is recovered and examined Vixen will return from self-imposed exile to tell us what the report on it means.
 
Happy to see you back, captain. Sorry you missed last month's futile fringe reset.

Maybe when the wreck's ramp is recovered and examined Vixen will return from self-imposed exile to tell us what the report on it means.

The official report will only credit Svensson with recovering one ramp, when early news reports (which are always definitively reliable and accurate) say that he recovered seven. Something something therefore coverup.
 
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