Singularitarian
Banned
- Joined
- Jul 14, 2009
- Messages
- 1,007
What the heck are you on about?
A photon from its point of view does not experience time pass at all. In fact, it does't even have a proper existence at all. It's death and birth are simultaneously the same thing. It's internal experience is stuck in null trajectories, making the time dilation infinitely-stretched.
The photon has what’s called a 4-momentum [latex]p^{\mu}[/latex] and a 3-momentum [latex]P_i[/latex]. The photon in relativity
is said to move along a null trajectory so [latex]p^{\mu}p_{\mu}=0[/latex], but in considering the energy, traditionally given as [latex]E[/latex] and the 3-momentum this is [latex]-E^2+|p|^2=0[/latex]. The path it moves through space from
an observers point of view is completely different to that of a photons however. In usual metric structures, you have [latex]p^{\mu}p_{\mu}=-M^2=+E^2-(p^1)^2+p^{2}_{j}[/latex] with a perpendicular component given as [latex]j[/latex] in
this case.
Only from our perspective can a photon be seen to move through time.
A photon from its point of view does not experience time pass at all. In fact, it does't even have a proper existence at all. It's death and birth are simultaneously the same thing. It's internal experience is stuck in null trajectories, making the time dilation infinitely-stretched.
The photon has what’s called a 4-momentum [latex]p^{\mu}[/latex] and a 3-momentum [latex]P_i[/latex]. The photon in relativity
is said to move along a null trajectory so [latex]p^{\mu}p_{\mu}=0[/latex], but in considering the energy, traditionally given as [latex]E[/latex] and the 3-momentum this is [latex]-E^2+|p|^2=0[/latex]. The path it moves through space from
an observers point of view is completely different to that of a photons however. In usual metric structures, you have [latex]p^{\mu}p_{\mu}=-M^2=+E^2-(p^1)^2+p^{2}_{j}[/latex] with a perpendicular component given as [latex]j[/latex] in
this case.
Only from our perspective can a photon be seen to move through time.