• Quick note - the problem with Youtube videos not embedding on the forum appears to have been fixed, thanks to ZiprHead. If you do still see problems let me know.

General Relativity, Acceleration, Gravity...

garys_2k said:
A background question: At very high speeds the traveler should see his clock appear to read time normally, but he should perceive his motion to be fantastic, right? I mean, from his point of view he should be able to cover what we see as a light year's distance in a day, correct?

What looks like a light year to us, looks like a much shorter distance to him, which is why he can sees himself traverse the distance so much faster. Length contraction and time dilation go hand in hand. So he sees the landscape (everything that's stationary for us) as passing him by at the same speed that we see him passing by (something a little under light speed) - so in that sense no, he doesn't see his speed as being fantastic. Just as his clock doesn't agree with our clock, his perception of the distance between objects along the direction of motion doesn't agree with ours.

Edited to clarify.
 
garys_2k said:
A background question: At very high speeds the traveler should see his clock appear to read time normally, but he should perceive his motion to be fantastic, right? I mean, from his point of view he should be able to cover what we see as a light year's distance in a day, correct?

Except, of course, that he'd measure it as a lot shorter. He might get a bit giddy at measuring a couple of really flat stars a couple of meters apart, though.
 
Thanks again, that's what I thought. Abel would see what had formerly been a light year's distance as a light day, but that would be consistent with the apparant spatial distortion (direction of travel dilation) he also noted.

Abel reaches the rock in (to him) one light day. He's been keeping an eye on Bob's clock back on earth during the trip. What (generally, if you will) would he see Bob's clock read when he got to the rock?

It was a day's journey on his own clock, 366 day's duration on Bob's. I'm guessing now, after thinking harder about it, that he'd see Bob's clock read only a small fraction of a day since he took off. Maybe a few minutes after his departure. If things were proportional, he'd see about 1/365 of a day, or just under four minutes had elapsed on Bob's clock.

Reasonable so far? I doubt the math's that simple, but I think conceptually and directionally I have this better now.

I will await an answer before taking the next baby step (which is, what he would see happening on earth while he dwelled at the rock for a minute).
 
Originally posted by garys_2k
It was a day's journey on his own clock, 366 day's duration on Bob's.
Hmm...can that be?

Now that we're really getting into the details, we should make sure that the numbers are right. If Abel travels at 365/366 c, his clock runs at about 1/13.5 the rate of Bob's clock. (See, e.g., http://en.wikipedia.org/wiki/Time_dilation) So, the trip doesn't take him just a day; it takes him about 366/13.5 = 27 days.
Abel reaches the rock [...]. He's been keeping an eye on Bob's clock back on earth during the trip. What (generally, if you will) would he see Bob's clock read when he got to the rock?
It seems easiest to figure this out from Bob's point of view: Abel reaches the rock a year and a day after he left Earth. If Abel looks through his telescope back at Bob's clock on Earth, the light entering his eye at that moment left Earth a year earlier, because the rock and Earth are a light-year apart. So, he sees Bob's clock show that it's one day after he left.
 
Metullus said:
Err... matter is always "experiencing forces due to gravity". Objects in orbit are "in orbit" because of Earth's gravity; otherwise they would just keep on going in a straight line after launch.
If you are in a spaceship in orbit, you could not tell the difference between that and being way out in interstellar space. You would not experience a force as you do standing on the surface of the earth.

The force you feel when standing stationary on the surface of the earth is equivalent to the force you would feel if there was no gravitic field, but the ground was accellerating upwards at 9.8 m/s.

An orbit is an inertial frame of reference. An orbiting object is travelling on a geodesic in curved spacetime.

But I don't know what effect any of this has on time dialation.
 
69dodge said:
Hmm...can that be?

Now that we're really getting into the details, we should make sure that the numbers are right. If Abel travels at 365/366 c, his clock runs at about 1/13.5 the rate of Bob's clock. (See, e.g., http://en.wikipedia.org/wiki/Time_dilation) So, the trip doesn't take him just a day; it takes him about 366/13.5 = 27 days.It seems easiest to figure this out from Bob's point of view: Abel reaches the rock a year and a day after he left Earth. If Abel looks through his telescope back at Bob's clock on Earth, the light entering his eye at that moment left Earth a year earlier, because the rock and Earth are a light-year apart. So, he sees Bob's clock show that it's one day after he left.
Thanks! The right numbers help, too.

So, from Bob's point of view, Abel's clock did run slowly, as 27 days went by on it while 366 days went by on earth. From Abel's point of view 27 days elapsed but he saw only 1 day's time pass on earth.

Next, then, if he stops at the rock and looks back at earth, what will he continue to see? I expect he'd just see time continuing normally (but displaced by what looks to him like 26 days).

In other words, if he'd left just after midnight on January 1, his time would be early January 28 (let's say the 27 days was exact). He would see earth's time as early January 2. As he watched Bob's clock tick on earth it would appear to run normally (one of Bob's seconds would be the same as one of his seconds).

Right with this part?
 
pmurray said:
But I don't know what effect any of this has on time dialation.

There is an interesting connection.

If you drop a clock, ignoring air resistance, and it passes some other clocks on the way down (say, one at the top of a mountain, and one at sea level, etc.) then as it passes those clocks, you can work out the relative rates from their instantaneous speed as they pass. This provides another, sort-of backward way to look at GR.
 
pmurray said:
If you are in a spaceship in orbit, you could not tell the difference between that and being way out in interstellar space. You would not experience a force as you do standing on the surface of the earth.

The force you feel when standing stationary on the surface of the earth is equivalent to the force you would feel if there was no gravitic field, but the ground was accellerating upwards at 9.8 m/s.

An orbit is an inertial frame of reference. An orbiting object is travelling on a geodesic in curved spacetime.

But I don't know what effect any of this has on time dialation.
Yeah, well, I finally found a nit to pick in a SMM&T thread and by god I wasn't gonna let the opportunity pass. By the way, did you notice the skillful way I used "Err..." when I started that post? Just like the pros, huh? :)
 
garys_2k said:
Thanks! The right numbers help, too.

So, from Bob's point of view, Abel's clock did run slowly, as 27 days went by on it while 366 days went by on earth. From Abel's point of view 27 days elapsed but he saw only 1 day's time pass on earth.

Next, then, if he stops at the rock and looks back at earth, what will he continue to see? I expect he'd just see time continuing normally (but displaced by what looks to him like 26 days).

I think you're still getting hung up on see versus measure.
 
epepke said:
I think you're still getting hung up on see versus measure.
That's possible, but what would he see, please? I'm trying to settle this in my mind.

Then, what would he measure, and how? Would he "measure" by taking what he sees and applying some correction, or would measurement tools react differently than what he sees?

I'm not trying to pick nits, I really don't understand. Baby steps, please. Someone posted earlier that as soon as he stopped that he'd see a whole bunch of time fly by on earth, all in a huge rush. I doubt that's right. Is it?. I really think Able would see time proceeding normally on earth, at the same pace as time is proceeding for him, but with a 26 day offset.

Settling this will help quite a lot.
 
garys_2k said:
Then, what would he measure, and how? Would he "measure" by taking what he sees and applying some correction, or would measurement tools react differently than what he sees?

When talking about relativity, a term often used (and often not fully understood by novices) is "observe". It's an idealized notion of what you would measure if you had an infinite lattice of clocks and rulers throughout space, which was moving in the same reference frame as you, and which could instantly measure anything, anywhere, in whatever coordinate system you were currently in. Of course, such a thing is impossible, but you can get basically the same answer if you take what you see (which is also the only thing you can measure) and correct for the fact that the light took time to reach you.

I'm not trying to pick nits, I really don't understand. Baby steps, please. Someone posted earlier that as soon as he stopped that he'd see a whole bunch of time fly by on earth, all in a huge rush. I doubt that's right. Is it?

Well, I can't remember what everyone said and it would take a while to go back over everything. But what the traveling twin SEES when he stops at that distant star is that the earth-bound twin's clock is no longer running slow (it was while he was traveling away from earth), but there's NO discontinuity or rapid speed-up in what he sees.

Here's a way to think about what he sees that may make it a little easier. If you draw out the earth twin's time line (in his frame, a vertical line), then mark off intervals along the line. These are ticks on his clock. From each tick point, draw out a light cone, in the direction of the traveling twin. Wherever the traveling twin's timeline intersects that lightcone, that's when the traveling twin sees that tick on the earthbound twin's clock. When the traveling twin is moving away from earth, these intersections are spaces farther apart, when he's traveling back, they're closer together. But nothing special happens to the interval between receiving ticks, or which ticks he sees, at the turnaround point. So there's nothing weird about what he sees.

What he observes is something entirely different, though. What he observes is based upon his calculations for where the earthbound twin is at the same time. But "same time" changes meaning when you change reference frame, so the calculation changes, even though what you see doesn't do anything surprising. It's an artifact of that change in reference frame, and if you try to invest too much meaning into it, you can get yourself into all sorts of trouble, and I'll give you an example. If you're approaching earth at close to c, but then reverse direction while you're still far away, the time you "observe" on earth after the reversal is actually earlier than the time before you reverse. But time obviously doesn't actually go backwards, and you never SEE anything weird happen during the turn around.
 
garys_2k said:
That's possible, but what would he see, please? I'm trying to settle this in my mind.

Then, what would he measure, and how? Would he "measure" by taking what he sees and applying some correction, or would measurement tools react differently than what he sees?

I'm not trying to pick nits, I really don't understand. Baby steps, please. Someone posted earlier that as soon as he stopped that he'd see a whole bunch of time fly by on earth, all in a huge rush. I doubt that's right. Is it?. I really think Able would see time proceeding normally on earth, at the same pace as time is proceeding for him, but with a 26 day offset.

OK. Some of the concepts fit together, like pieces of a puzzle, so it's hard to know what to start with first. Once you have the whole puzzle, it's easier to see how the pieces fit together.

Some people like to say that, when we are looking at Barnard's Star, which is about 6 LY away, we are seeing it as it was 6 years ago.

That word, "ago," needs some investigation. All we really know is that we're seeing it here, now. On observer near Barnard's Star would also see us 6 years ago. So this leads to a seeming paradox, and we have to understand "ago" with respect to something that we might call "now."

In Galilean/Newtonian mechanics, this is easy. We just synchronize our clocks with an instantaneous signal, and that defines "now" for the both of us.

But we can't do that with Lorentzian/Einsteinian mechanics. So instead, we imagine a line of clocks reaching from here to Barnard's Star. Let's say that they're all synchronized by a distant supernova, at right angles to the line, far enough away that the difference in the distance along the line is insignificant.

This line of clocks is approximately what Dr Fendetestas called a "simultaneity line" for what we call "now." We extend this idea to fill all of space, or at least as much as we need, at known distances and known times, and we call this our reference frame. Fortunately, under SR, and with the examples in this thread, we only have to concern ourselves with one spacial dimension in the direction of travel, so we can just think of the line.

Already, there's a problem. If our local clock reads 12:00, we will see a clock one light-hour away as reading 11:00. But we make our measurements with respect to our entire frame, so we think of it as being 12:00 everywhere on our frame. So what we see isn't what we measure.

(The concept of a "simultaneity line" is a bit more complex; there will be a 12:00 simultaneity line and a 12:37 simultaneity line, and so on. So you can think of a bunch of simultaneity lines. But there will always be a "now" simultaneity line, and you can extrapolate the other clocks from your clock where you are. I'll omit the "now" in subsequent discussion and just assume that Abel always makes measurements for his now.)

We imagine our frame as moving with us, even accelerating. Maybe each clock has a rocket on it, and the rockets go on and off as a result of other distant supernova explosions.

When the rockets are off, with two reference frames, we have SR. We make our time dilation measurements or observations with respect to the closest clocks in the other reference frame. Under SR, we will see all of our clocks moving at the same rate. Under acceleration, as explained earlier, we will see clocks "above" us going faster. (Define "above" as in the direction of acceleration.)

Someone posted earlier that as soon as he stopped that he'd see a whole bunch of time fly by on earth, all in a huge rush. I doubt that's right. Is it?

Now it should be understandable. To keep it simple, let's just consider the moment after Abel has mostly decelerated, just before he turns off the rockets. So his frame and the Earth frame are close enough to stationary relative to each other that we don't have to worry about SR time dilation. Abel does the measurements with respect to the clock in his reference frame closest to Earth. He will measure this clock as going very, very fast due to the acceleration. But since it's close to the Earth clock and not moving much relative to it, he will also have to measure the Earth clock as going very, very fast. So, according to his measurements, the Earth clock must be going very, very fast. So he will measure a bunch of time going by quickly. Of course, what he sees involves light getting to him, so the change will be much more gradual than what he measures, and it will take the whole trip back to finish.

If you recall, I said that you could work out the twin paradox either with SR or GR. If you read this post carefully, you will have noticed that there's a seeming "cheat," which is actually a little bit of SR. While Abel was just moving, his simultaneity line always seemed normal. He could look at the serial numbers of all his clocks, look up the distance in a book, compare the distance from the reading on the display and the speed of light, and everything would be OK. While accelerating, the rates of the clocks would go all wahoonie-shaped. So, after the acceleration, you might think that his book wouldn't work any more. This is quite correct.

From SR, you already know that while your simultaneity line looks horizontal (constant t), the simultaneity lines of other moving frames would appear to be at an angle to yours, so you would disagree on what events are simultaneous, except locally.

If Abel got a new simultaneity line by resynchronizing all of his clocks to another supernova explosion, it would appear to be at an angle to his old simultaneity line (the new one would be horizontal). It would be at just the same angle as another inertial frame already going in the other direction.

This is why you can explain the Twin Paradox under SR. If you just switch reference frames, you throw your old book away and use the new captain's book.

Or you can do it in GR. I won't try to give the math, just the zen. When you're not accelerating, you can imagine all your simultaneity lines stacked up, forming a grid. This is your spacetime reference frame. It looks like a plain Cartesian grid, and it's called "flat spacetime" for this reason. Abel is looking at his clock, which he's holding right up to his eye, so he always sees himself as going straight up through time.

As Abel accelerates, his simultaneity lines according to his book seem to curve all around him. But he still thinks he's going straight up in time, at the same rate. When he turns the rockets off, spacetime will flatten out again all around him. But he will, in the meantime, have gone through time to another part of the curved grid where the simultaneity lines are at a different angle to the time line, so he will see his old simultaneity lines at a different angle now.

Einstein had a cute name for a curved frame. He called it a "mollusc," evoking the shape of a section of a snail's shell.
 
Originally posted by garys_2k
So, from Bob's point of view, Abel's clock did run slowly, as 27 days went by on it while 366 days went by on earth. From Abel's point of view 27 days elapsed but he saw only 1 day's time pass on earth.

Next, then, if he stops at the rock and looks back at earth, what will he continue to see? I expect he'd just see time continuing normally (but displaced by what looks to him like 26 days).

In other words, if he'd left just after midnight on January 1, his time would be early January 28 (let's say the 27 days was exact). He would see earth's time as early January 2. As he watched Bob's clock tick on earth it would appear to run normally (one of Bob's seconds would be the same as one of his seconds).

Right with this part?
Yes, that's what he sees. There's some trickiness involved in how he ought to interpret what he sees, because the light he sees now on the rock was emitted some time earlier by Bob's clock which is some distance away. But you are correct about what Abel sees.

How about what Bob sees? You wrote, "from Bob's point of view, Abel's clock did run slowly, as 27 days went by on it while 366 days went by on earth." There is a sense in which this is true, but it's a different sense than what we just said about Abel's point of view. On day 366 on Earth, Bob will not see Abel land on the rock. He won't see the landing for another year. When he finally does see Abel land, after two years and day, he will, naturally, also see Abel's clock read Jan 28 because that's what Abel's clock did in fact read during the landing. Bob can then figure out, based on the light-year distance to the rock, that Abel had landed a year earlier, i.e., on day 366.

What Bob actually sees on day 366 is Abel and his clock at approximately the halfway point of their journey. (Slightly further than the halfway point, because Abel is travelling slightly slower than lightspeed.) So he sees Abel's clock show approximately 13.5 days of elapsed time, rather than 27.
 
Originally posted by epepke
There is an interesting connection.

If you drop a clock, ignoring air resistance, and it passes some other clocks on the way down (say, one at the top of a mountain, and one at sea level, etc.) then as it passes those clocks, you can work out the relative rates from their instantaneous speed as they pass. This provides another, sort-of backward way to look at GR.
Ha. That is interesting. Thanks.
 
Back up here a little bit. I thought time dialation is only really noticable when we approach the speed of light. Something in a higher orbit no matter how much acceration gravity is applying to it is nowhere near that speed. Could it be another effect of gravity on the decay rate of cesium instead? Why are we assuming that its time thats actually changing here?

If it was a mechanical clock I could see gravity have a slight effect on it too, but what about a quartz clock?
 
MoonDragn said:
Back up here a little bit. I thought time dialation is only really noticable when we approach the speed of light. Something in a higher orbit no matter how much acceration gravity is applying to it is nowhere near that speed. Could it be another effect of gravity on the decay rate of cesium instead? Why are we assuming that its time thats actually changing here?

If it was a mechanical clock I could see gravity have a slight effect on it too, but what about a quartz clock?

No. Read my explanation of clocks under acceleration.

Time dilation due to high speeds and changes in the rate of clocks due to acceleration/gravity are different effects.

(Actually, this is a lie. They're part of the same effect, but only if you already understand GR. However, if you don't understand GR, you have to pretend they're different effects.)

Furthermore, time dilation effects are noticeable at much lower speeds, if you're doing precise measurements of time. The GPS satellites, for example, are highly sensitive to them. They are so sensitive that they seem to be detecting slight fluctuations away from what we would see assuming a smooth GR (gravity waves? quantum fluctuations? It's an interesting problem.)

Note that this isn't that hard, electronically. A nanosecond in time corresponds to a bit more than a foot in space, and a gigahertz system, which is probably slower than your computer, can resolve that.

BTW, when we talk about relativity, we generally use idealized light clocks, with a pulse of light bouncing back and forth between two mirrors. These, assuming the postulates of relativity, are the most accurate clocks available. So effects of acceleration such as, say, bending the parts of a mechanical clock, are neglected.
 
But according to some recent articles I've read, doesn't gravity directly affect the speed of light? To use that as a measurement would certainly be distorted.
 
MoonDragn said:
But according to some recent articles I've read, doesn't gravity directly affect the speed of light? To use that as a measurement would certainly be distorted.

That goes back to what you mean by speed of light. And that's generally looked at in terms of the relationship between time (clocks) and space (rulers). If clocks run slow (and no, I don't mean mechanical clocks, I mean any possible or even idealized clock), then yes, in a sense, the speed of light also "changes". But not in the sense that, locally, it's still always the same 3x10^8 m/s. The speed of light is still a constant - it's really TIME that's changing here. It also helps to recall that the speed of light isn't something peculiar to light either - any massless particle will travel at c. Light doesn't define the relationship between space and time, rather the relationship between space and time uniquely determines the speed at which light travels. There's absolutely no problem with using light to make your clocks, because the speed of light can ONLY change by changing (slowing down or speeding up) the passage of time.
 
Ok I found an article about how it affects atomic clocks :

http://www.ldolphin.org/constc.shtml

However I am still not too sure about the affects on the light clock. Is it due to the affect of gravity altering the curvature of space? I thought all of that was still conjecture?
 
MoonDragn said:
Ok I found an article about how it affects atomic clocks :

http://www.ldolphin.org/constc.shtml

However I am still not too sure about the affects on the light clock. Is it due to the affect of gravity altering the curvature of space? I thought all of that was still conjecture?
Nice religous woo site, there. Light's speed has been decreasing over time, eh? Funny, that's not at all what almost all of the evidence shows (and the stuff that doesn't is usually either clearly flawed or the variation is within experimental error, so is less-clearly flawed).

Regarding gravity changing clocks' running time, yes, it is due to the bending of spacetime. That's what I've been trying to get my brain around. I'm getting there, too.
 

Back
Top Bottom