Ziggurat
Penultimate Amazing
- Joined
- Jun 19, 2003
- Messages
- 61,643
It's going to be a bit on the bright side so I would suggest wearing shades
The question is: how much weight does this amount to?
I think your calculation is off, probably because of some assumptions about how the photons apply pressure.
For photons (or any ultra-relativistic particle), the pressure is given by
P = (1/3) E/V
Using E = mc2 to find an equivalent mass, this gives
P = (1/3) (m/V) c2
Solving for the effective density gives
m/V = 3 P/c2
Sticking in 1 atmosphere of pressure (about 105 Pa) and c = 3x108 m/s, this gives us a density of 3x105 (kgm/s2/m2)/[3x108(m/s2)]2 = 3.3x10-12 kg/m3
So... significantly heavier than your answer, but still very light indeed, in terms of mass.
But in terms of energy? Well, 105 Pa = 105 J/m3. That might not seem like a lot (it's far less than 1 kW hr, so we're talking less than a penny per cubic meter), but this energy is flying around at c. The power involved is spectacularly high, around 3x1013 Watts, or 30 terrawatts. The entire world generates about 2.3 Terrawatts of electricity, to give you some idea. So it wouldn't take much deviation from perfect reflection to absorb this energy in very short order, unless your balloon is at very, very high temperature. You can figure out the temp from the page I linked to (use the first equation from the table), but that requires multiple physical constants and I'm too lazy right now.