Hello,
I am trying to work out the probability that a pack of trading cards contains new cards or cards that I already have.
I am assuming that there are 100 cards in the set and that I already have 50 cards. Each pack contains 5 cards and all cards in a pack are different.
If I define the variable X as the number of cards that I do not already have, then what is the probabilty that X = 0, X = 1 and so on?
I thought about treating the pack as 5 successive draws
In that case the probabilty that the first card is new is just 50/100 but the proabilty that the second card is new depends on the outcome of the first card drawn.
If the first card was new then the probabilty that the second card is also new is 49/99 as there are now 49 cards still to be collected and the second card can't be the same as the first card. So the probabilty that the first two cards are new is 50/100 times 49/99 or 0.247.
If I already have the first card then the probability that I already have the second card is 49/99, so the probability that the first two cards are ones that I already have is also 0.247. The probabilty that only 1 of the first two cards is new can be worked out as one minus the other probabilities.
Scaling this up to three, four and five cards will be complicated. Is there a simpler way?
I am trying to work out the probability that a pack of trading cards contains new cards or cards that I already have.
I am assuming that there are 100 cards in the set and that I already have 50 cards. Each pack contains 5 cards and all cards in a pack are different.
If I define the variable X as the number of cards that I do not already have, then what is the probabilty that X = 0, X = 1 and so on?
I thought about treating the pack as 5 successive draws
In that case the probabilty that the first card is new is just 50/100 but the proabilty that the second card is new depends on the outcome of the first card drawn.
If the first card was new then the probabilty that the second card is also new is 49/99 as there are now 49 cards still to be collected and the second card can't be the same as the first card. So the probabilty that the first two cards are new is 50/100 times 49/99 or 0.247.
If I already have the first card then the probability that I already have the second card is 49/99, so the probability that the first two cards are ones that I already have is also 0.247. The probabilty that only 1 of the first two cards is new can be worked out as one minus the other probabilities.
Scaling this up to three, four and five cards will be complicated. Is there a simpler way?