Split Thread The validity of classical physics (split from: DWFTTW)

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That should give you an average force proportional to v2, then. There's one factor of v because the momentum transferred per particle is proportional to v, and there's another because the number of particles the thing collides with per unit time is also proportional to v. So I don't see how you can get an exponential out of that.

Right you are. It seems to match a function of the form v=v0/(kt+1). Just looked like an exponential decay at first glance.
 
I agree completely. But who is actually being deceived and who are these that can see they are being? You're being rather ambiguous again!
No ambiguity. I am not deceiving you. I like magic because it shows how lame we are at observing, and how often we come to the wrong conclusions, even in general.

Here's a simple question that I hope you'll answer for me. It may seem a rather odd thing to ask but I believe that an open and honest answer from you can only help to support your position - which I'll assume for now is that you are in fact acting in good faith, and not deliberately setting out (in general at least) to deliberately deceive or frustrate others who have contributed to this thread.
Understood. I have never knowingly mislead anyone on this forum, here or elsewhere.

So here's the question. Have you come to the realisation that any part (at all) of your previous understanding of physics was incorrect as a result, directly or indirectly, of anything written in this thread and its parent?
No. Some of what Sol_invictus has said about EM and momentum may have a point. I remember seeing something like this before, regarding TEM waves, I think, but that is not of direct consequence to the treadmill.
Mixed opinions as to how the cart works, or should work, but that is straight forward engineering.
The treadmill is nonsense. That is not rhetoric. It is stupefyingly wrong.

For extra credibility, can you tell us what it was that you used to incorrectly believe and how you see that now? (Obviously something of some significance and relevance to the cart and treadmill rather than a very tiny detail in more or less unrelated area will probably carry more weight.)
Extra credibility? Is there a sale on?
There is nothing, Clive, but I am not one for belief.

Now, it could be that your honest answer to the above is "no". But I think I would find that somewhat surprising and therefore harder to believe than hearing you say something like, "Yes, I was wrong about some things, and here is an example....", and then proceed to show us something you have learned.
Well, it is no.

I'm happy to do the same if that seems more equitable. Just ask! However I don't think people will be nearly as interested in what I might have to say about my own knowledge or lack of it as what you might have to say about yours given the circumstances.

Not directed at you Clive, but "admitting I am wrong" is given pride of place. I find this to be extraordinary.
It's giving yourself a slap on the back for being wrong, while suggesting that not only is the admission call for celebration, but the very improbability of the error itself. Is it possible to be more conceited than that?

So, if I am wrong I will simply tell you. I won't dance on the simple admissions of others.
 
That is essentially so, JJCote. It was not my argument, but Sol_invictus' support for his abuse of Rayleigh's formula for steady flow.
The point is moot. The question is for steady wind or water. Balloons can exploit wind variation to increase their velocity to the mean speed. I expect that some devices could do better.
No news there for you, I hope, JJcote.

The question stands. For a 0.1 kg balloon, with a volume of 0.21 cubic meters, a cross-sectional area of 0.427 square meters, and a radius of 0.369 meters, assume a steady wind speed of 1 m/s, a drag coefficient of 0.4, and an air density of 1.293 kg per cubic meter. Release the balloon from its tether. What will the "terminal velocity" of the balloon be? I assert that it is 1 m/s, and in fact that it will reach a speed of 0.9995 m/s within 3.2 seconds after being released (somebody check my calculation on that part). As more time elapses, the speed of the balloon will asymptotically approach 1 m/s. Do you think the number will be different? Either calculate it, or tell us what additional information you need, or tell me how to do the calculation. The problem that I have with figuring out what the speed is in the humberverse is that as far as I can tell, there are two different airspeeds that the balloon experiences simultaneously, one being a headwind and the other a tailwind, and I have no idea what they would be.
 
The treadmill is nonsense. That is not rhetoric. It is stupefyingly wrong.

Mark Drela claims the treadmill is not wrong. So on one side we have:

- Everyone but humber on this forum
- Chapter 1 of Intro to Highschool physics
- Mark Drela (PhD in Aero, MIT professor of Aero, and one of the best minds in Aero today).


And on the other side we have:
- humber


Yeah - I suppose this would come down to a coin toss.
 
Mark Drela claims the treadmill is not wrong. So on one side we have:

- Everyone but humber on this forum
- Chapter 1 of Intro to Highschool physics
- Mark Drela (PhD in Aero, MIT professor of Aero, and one of the best minds in Aero today).


And on the other side we have:
- humber


Yeah - I suppose this would come down to a coin toss.

Not quite. Reference for Mark Drela personally giving support for you treadmill.
 
Hey, if you want to see humber's older brother in action (GMB - gumby?), pop over to the "theory of relativity is wrong" thread.
 
Not quite. Reference for Mark Drela personally giving support for you treadmill.

Are you going to admit you're wrong if I produce that evidence?

Hell, Mark Drela could personally come to your home, show you three forms of government issued picture I.D., tell you the treadmill test as demonstrated by JB and spork is absolutely representative of an outdoor downwind test, re-tell the whole story through interpretive dance, and finally sign documents to that effect, and have them notarized - and you'd tell us "that's not what he meant".
 
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I'll let you attack the argument before I provide evidence that it comes from Mark Drela. No point in bringing matter and anti-matter together if I don't need to after all.

So here's how it goes...


Critic says:

The idea of extracting more power from the wind than is there seems to be like the Underwear Gnomes on South Park...

Stick to the premise, wind powered, not multiple HP treadmill power...


Drela responds:

Hmm. I think this statement identifies one major misconception which causes so much confusion: The idea that "the wind" provides the power. It doesn't, at least not to all observers.
An observer in a hot-air balloon always feels zero wind, so to him the concept of "wind power" seems strange. To him, the DDW cart is clearly "ground powered", by the ground moving past the balloon.

It's better to say:
Sailboats, iceboats, DDW machines, Dynamic Soaring gliders, are all powered by the velocity difference between two media.
This works because a velocity difference is the same for any observer, regardless of his own motion.

Some examples of the two media, for specific machines:
DDW cart, land yacht: Airmass and ground
DDW boat, sailboat: Airmass and watermass
DS glider, albatross: Airmass above and airmass below a shear layer

So it seems (to all other sentient beings) that he also laid to rest your notion that a hot air balloon doesn't drift at wind speed. Although I realize it won't seem that way to you.
 
The question stands. For a 0.1 kg balloon, with a volume of 0.21 cubic meters, a cross-sectional area of 0.427 square meters, and a radius of 0.369 meters, assume a steady wind speed of 1 m/s, a drag coefficient of 0.4, and an air density of 1.293 kg per cubic meter. Release the balloon from its tether. What will the "terminal velocity" of the balloon be? I assert that it is 1 m/s, and in fact that it will reach a speed of 0.9995 m/s within 3.2 seconds after being released (somebody check my calculation on that part). As more time elapses, the speed of the balloon will asymptotically approach 1 m/s. Do you think the number will be different? Either calculate it, or tell us what additional information you need, or tell me how to do the calculation. The problem that I have with figuring out what the speed is in the humberverse is that as far as I can tell, there are two different airspeeds that the balloon experiences simultaneously, one being a headwind and the other a tailwind, and I have no idea what they would be.

No need, there is a similar example given in the text. The formula is an approximation based upon the simplification that (V-Vb)^2, can be V-Vb. There is no doubt that some objects can get close to the wind, bubbles being one example, but not reach it. In this case, the drag that the bubble sees ahead of it is so low, that is can get close to windspeed before that drag, exceeds the force available to it. Unless you can make that zero, and so contradict Newton, the bubble will not reach windspeed.

The author simply ignores this limitation, because he says "they usually follow the wind flow". He uses that assumption to show that it will track variation, because the accerleration is acceptable, but the mean speed will vary according to circumstance, including the frequency and distribution of gusts, and the 'crest factor' the ratio of mean to peak winds. The definition of 'mean' is quite wide, nd perhaps not the one you are assuming to be so.
You don't get an entire course of the nature of bacteriological balloons on one page, jjcote.

Of course, if you are correct, you should also be able to show that all objects can do the same, not just a special example of something that is like air. I said this before, with the 'water canoe'. The more it is 'like' water, the closer it will approach waterspeed. Balloons are close, bubbles closer, but not at all most objects, including sails and windcarts.
 
No need, there is a similar example given in the text.

I repeat my question: if the "terminal velocity" of the balloon is not 1 m/s, then either tell us what it is, or tell us what additional information is needed to calculate it. You have clearly stated that the propulsion from the wind will balance out with the drag at some speed. What is that speed?

Hey spork, did you tell Mark that I said "hi"?
 
I'll let you attack the argument before I provide evidence that it comes from Mark Drela. No point in bringing matter and anti-matter together if I don't need to after all.

Not Spork?
Quote:
The idea of extracting more power from the wind than is there seems to be like the Underwear Gnomes on South Park...

Stick to the premise, wind powered, not multiple HP treadmill power...


Drela responds:
Hmm. I think this statement identifies one major misconception which causes so much confusion: The idea that "the wind" provides the power. It doesn't, at least not to all observers.
An observer in a hot-air balloon always feels zero wind, so to him the concept of "wind power" seems strange. To him, the DDW cart is clearly "ground powered", by the ground moving past the balloon.

Here he has wind-power and ground-power between double quotes. They are notional to Drela. He is using them to define a "major misconception".

It's better to say:Sailboats, iceboats, DDW machines, Dynamic Soaring gliders, are all powered by the velocity difference between two media.
This works because a velocity difference is the same for any observer, regardless of his own motion.

Some examples of the two media, for specific machines:
DDW cart, land yacht: Airmass and ground
DDW boat, sailboat: Airmass and watermass
DS glider, albatross: Airmass above and airmass below a shear layer
"All powered by the velocity difference between two media". Yes, relative velocities. Airmass, in the cart's case. In other words, the difference between wind airmass, power, and ground, just like every critic avers.
In fact, he dismisses ground power as notional upon that basis.

You take that idea of relative velocities, the one that as you say every highshcool student understands, yet you don't, in order to make a completely false claim for your treadmill. There is not on iota of support for your claim here.

So it seems (to all other sentient beings) that he also laid to rest your notion that a hot air balloon doesn't drift at wind speed. Although I realize it won't seem that way to you.

Hot air balloons have an engine Spork, yes heat is an engine. Hot air ballons use altitude, and ride thermals. They have an operator who controls the engine as and when required. When will you appreciate that difference?

If this is the big string to your bow, then fire away.
 
Parsing humber

No ambiguity. I am not deceiving you.

I have never knowingly mislead anyone on this forum, here or elsewhere.



Mixed opinions as to how the cart works, or should work, but that is straight forward engineering.


The treadmill is nonsense. That is not rhetoric. It is stupefyingly wrong.
but I am not one for belief.
No ambiguity? Hmmm. Let's see, There are mixed opinions as to how the cart works. Humber's mixed opinions? Or mixed opinions on the forum generally? Ah, it must be others who have mixed opinions, because "that is straight forward engineering". Clear enough about that. If there were mixed opinions, they were someone else's.

Then some more clarity about the treadmill. What most people would consider beliefs. Yet humber is "not one for beliefs", he says. What does that mean, not to be "one for beliefs", yet unrhetorically state that something is stupefyingly wrong and nonsense? Does it mean that it is an absolute fact, which humber can discern like an absolute velocity? Does he mean that he doesn't bother with beliefs because he knows; mere mortals deal in beliefs? We might construe that, but who knows when what has been said is so ambiguous?

What about this then:
Not directed at you Clive, but "admitting I am wrong" is given pride of place. I find this to be extraordinary.
The first sentence is ambiguous immediately for not having a subject. Someone, we must assume, gives pride of place to the act of admitting they were wrong, but we're not told who that is. It might mean humber, if we choose to read it that way: he could be affirming his habit of saying when he's been wrong about something. That would add weight to his firm (absolutely unqualified) "No" to whether he was wrong about anything. On the other hand, it could be a criticism of how others hold such openness in high esteem, or a mere observation that they do. He finds it extraordinary, which suggests that perhaps the criticism of others is a more correct reading, as do some of the following.

But before we get to that - the whole thing started with an aside, "Not directed at you Clive, but". So, depending on whether humber thinks owning up to stuff is a good or a bad thing (I'm not sure now), he may or may not be saying that Clive does or doesn't do that and he doesn't hold it against him, and in the process insinuating that someone else may...or may not...and he does. Clear so far? Maybe the following will shed some light.

It's giving yourself a slap on the back for being wrong, while suggesting that not only is the admission call for celebration, but the very improbability of the error itself. Is it possible to be more conceited than that?
Yes, no, I mean, now it begins to appear that what is commonly considered a virtue humber sees as a vice. Admitting a mistake, saying sorry, giving way in an argument, seems to indicate to humber a self-aggrandisement, 'a slap on the back for being wrong' and 'cause for celebration'!

It also, curiously, seems to suggest to him that when we say we were wrong we express the conceit that it doesn't happen very often. Perhaps the more we say we were wrong, then, the more arrogant we show ourselves to be, and by stating so clearly (if qualified a little) that he was never wrong about anything here in this thread, humber is obviously being humble. Humble people don't slap themselves on the back for being wrong every ten minutes, after all! (Oh, I know, you hawk-eyed people, I've edited out the bits where he said there were things he learned about something-or-other - VEM or PIM or I don't know what - but that had nothing to do with anything anyway; let's forget that shall we?)

Is that what he means, then, that saying you were wrong is arrogant? There is hardly any point in asking him. Ah, but there's even more ambiguity to come. Have I just misunderstood the whole tenor of his meaning?...

So, if I am wrong I will simply tell you.
If he's wrong, he'll simply tell us!? He must think it's good to own up to it when you're wrong. That's what I thought several paragraphs ago. I was wrong. And then I was wrong again. My God! How conceited of me! He's expressed it so clearly. He will simply tell us if he's wrong.

And, to summarise, just in case we were in any doubt as to his meaning, we get it all wrapped up in a nutshell, final clarity par excellence:
I won't dance on the simple admissions of others.
Oh.

Deep. A koan? Accusative, but vaguely so, and rather superior-sounding.

Are you glad you asked, Clive? If humber was wrong, he'll tell you, unless he's too self-effacing for that.
 
Spork was right, no sense casting pearls before swine.

Regarding humber's post about Mark Drela's response to spork's question: humber, that is one of the most self-serving purposely misinterpreted pile of garbage that you've spouted so far. You absolutely have no desire to learn. It is manifestly evident that you can't let go of your flawed understanding. At one point I thought it was possible to help you past this, but it can't happen until you can accept that you are wrong.
 
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I repeat my question: if the "terminal velocity" of the balloon is not 1 m/s, then either tell us what it is, or tell us what additional information is needed to calculate it. You have clearly stated that the propulsion from the wind will balance out with the drag at some speed. What is that speed?

No, no, no.
The book is an introductory text to meteorological measurement.
In this case, the author is not concerned with the terminal velocity, but the ability to track the wind, against the mean flow (an indeterminate quantity).To simplify the equation, the force is assumed to be a linearly related to the difference in velocity of balloon and wind. It is not necessary that the balloon be even close to windspeed to display the variation.
It can travel slower. What they are NOT looking for is a balloon that "stays at zero velocity w.r.t the wind" because then, the result would be constant!
The balloon must let the wind "pass by it" or it would be held in a pocket of air traveling at the same velocity.

The author makes a simplifying assumption, then test his calculation ( not empirical measurement!) against a slow wind. Why?
To show that the variation is linear, that is a linear indicator of the difference of speed over a wide range of mean speeds. The indication will not be compressed by the absolute speed.

The speed of a natural fluid is vexed. If you place a hydrometer in a river, you will get variations across the river, as well as up or downstream.
To resolve this, dyes are used, because they behave "just like water" and the average journey time is used to compute the mean velocity.

Different objects in water, behave differently. If the river is glass like, I suppose a water beetle held by surface tension, will travel at the surface speed of the water. Some objects behave like Rayliegh says, some like Stokes, and others in a class where boundary conditions dominate.
If not, I would ask you to explain why some river borne sediments settle to the river bed according to their size, whereas very fine sediments travel to the sea?

If an object is dragged through oil, it generates a drag proportional to the square of the velocity. So, it is a parabola, passing through the origin. Let's say that at 10m/s that force is 20N. Now, I think you will agree that this is the same force, that the same object will experience, if held in a flow of the same oil at 10m/s?
If released, you say that the object will be accelerated in a manner that is the reverse of the dragged situation, so as to arrive at the origin (0,0) of the force parabola. Zero force.
No. The situations are no symmetrical. The force in the dragged case is external, unlimited, and directly coupled to the object. In the oil, the object gets its force not directly, but via drag. The object is not oil, so that makes the situation asymmetrical.
If the force on the object is the square of the difference, then it will be accelerated by a rapidly decreasing force. Ahead of the object, there will be the opposing force of drag. Now, this is turbulent, and not laminar, it is the wake of the fluid over the object. This force rises much faster than the applied force, so the object never reaches oilspeed.
Want a solution? Find a good CFD programme.
 
Now in the humberverse we find that fluids need to take Valium: "The speed of a natural fluid is vexed":boggled: I don't have any humber quotes yet, but this one ranks right up there:D
 
Spork was right, no sense casting pearls before swine.

Regarding humber's post about Mark Drela's response to spork's question: humber, that is one of the most self-serving purposely misinterpreted pile of garbage that you've spouted so far. You absolutely have no desire to learn. It is manifestly evident that you can't let go of your flawed understanding. At one point I thought it was possible to help you past this, but it can't happen until you can accept that you are wrong.

You have got to be kidding, Mender. One of my major criticisms of the treadmill is that it treats wind as a 'velocity'. I have repeatedly said that the is not a velocity, but a "moving mass". That is how Drela see's it, too.
That is what is missing from the treadmill. Every critic has said the same "there's no wind".

Yes, don't forget that he says "watermass" and included ground power as a misconception, or that the remarks are about the real world, and not treadmills. Other than that, a pearl.
 
You just noticed that? :D


No... I just have to remind myself of it from time to time.

I remember one time as a kid I was staying with a cousin with an old Commodore 64. After loading up one of the programs a sentence appeared, and whenever I pressed a button, it would be replaced by another.

At first, I was wondering what it was talking about, as I tried to find a connection between the statements. It took a couple more sentences before I realised the program was generating sentences by applying grammatical rules to randomly selected words.

Humber seems a bit like that... sometimes you can forget he's just spouting random gibberish.
 
http://journals.cambridge.org/actio...487EC4E690.tomcat1?fromPage=online&aid=367122


be sure to look fro the update that gives a non-intuitive correction

Yep, saw that. It was one of the 'special classes' I referred to. In this case, I think the author is arguing that the surface tension allows the objects to travel faster than other layers.
Other objects that are not boats are water beetles, tracking dyes and sediment.
Noteworthy is the fact that the channel is at an angle, so perhaps gravity may have something to do with it.
 
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